2 Comments
Oct 28Liked by Joel David Hamkins

I did it in terms of partial sums. For example the sum

1 + 2 + 5 + 2

corresponds to the partial sums 1, 3, 8, 10.

The largest partial sum is always n. The other partial sums can be any subset of {1, 2, ..., n-1}. Hence there are 2^(n-1) possible sums.

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author

That is a great argument. Wonderful!

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